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16=-9/2x^2
We move all terms to the left:
16-(-9/2x^2)=0
Domain of the equation: 2x^2)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
9/2x^2+16=0
We multiply all the terms by the denominator
16*2x^2+9=0
Wy multiply elements
32x^2+9=0
a = 32; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·32·9
Δ = -1152
Delta is less than zero, so there is no solution for the equation
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